Conservation of Momentum?

Derrick Cacioppo: M = m * vMa = 4500 kg * 6 m/s = 27,000 kg-m/sMa = Ma+b27,000 = (4500 + 7500) v v = 27,000/ (4500 + 7500)v = 2.25 m/sKEa = 0.5 MV^2 = 0.5 * 4500 * 6m/s^2 = 81,000 JKEa+b = 0.5 * 12,000 * 2.25^2 = 30,37581,000 - 30,375 = 50,625 J lost50625/81,000 = 62.5 % original energy lostQED...Show more

Cassidy Pangrazio: Conservation of momentumma V1 = (ma+mb) V2thusV2 = ma / (ma+mb) V1plug in the values and use your calculator. Initial kinetic energy isK1 = 1/2 ma V1^2final K energy isK2 = 1/2 (ma+mb) V2^2faction lost isFraction lost = (K1-K2) / K1use your calculator...Show more